23.07=3.14(4x)^2

Solution for 23.07=3.14(4x)^2 equation:

23.07=3.14(4x)^2

We move all terms to the left:

23.07-(3.14(4x)^2)=0

We get rid of parentheses

-3.144x^2+23.07=0

a = -3.144; b = 0; c = +23.07;
Δ = b2-4ac
Δ = 02-4·(-3.144)·23.07
Δ = 290.12832
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{290.12832}}{2*-3.144}=\frac{0-\sqrt{290.12832}}{-6.288}
=-\frac{\sqrt{}}{-6.288}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{290.12832}}{2*-3.144}=\frac{0+\sqrt{290.12832}}{-6.288}
=\frac{\sqrt{}}{-6.288}
$